إصلاح التمارين 29-30-31-32-33-34 صفحة 110 - إصلاح كتاب الرياضيات السنة السابعة أساسي

الأعداد العشريّة - الأعداد الكسريّة

إصلاح التمرين رقم 29 صفحة 110

\(\frac{5}{3}+\frac{15}{16}=\)

\(\frac{5×16}{3×16}+\frac{15×3}{16×3}=\)

\(\frac{80}{48}+\frac{45}{48}=\frac{125}{48}\)

*************

\(\frac{125}{48}-\frac{15}{16}=\)

\(\frac{5}{3}+\frac{15}{16}-\frac{15}{16}=\frac{5}{3}\)

*************

\(\frac{125}{48}-\frac{5}{3}=\)

\(\frac{5}{3}+\frac{15}{16}-\frac{5}{3}=\frac{15}{16}\)

إصلاح التمرين رقم 30 صفحة 110

أ)

\(\frac{5}{3}+\frac{15}{16}=\)

\(\frac{5×16}{3×16}+\frac{15×3}{16×3}=\)

\(\frac{80}{48}+\frac{45}{48}=\frac{125}{48}\)

*************

\(\frac{20}{21}-\frac{17}{35}=\)

\(\frac{100}{105}-\frac{51}{105}=\)

\(\frac{49}{105}=\frac{7}{15}\)

*************

\(\frac{14}{49}-\frac{4}{21}=\)

\(\frac{2}{7}-\frac{4}{21}=\)

\(\frac{6}{21}-\frac{4}{21}=\frac{2}{21}\)

*************

\(\frac{22}{35}-\frac{25}{42}=\)

\(\frac{132}{210}-\frac{125}{210}=\)

\(\frac{7}{210}=\frac{1}{30}\)

*************

ب)

\(\frac{17}{24}-\frac{5}{48}=\)

\(\frac{2×17}{2×24}-\frac{5}{48}=\)

\(\frac{34}{48}-\frac{5}{48}=\frac{29}{48}\)

*************

\(2,72-\frac{7}{25}=\)

\(\frac{272}{100}-\frac{7}{25}=\)

\(\frac{272}{100}-\frac{28}{100}=\)

\(\frac{244}{100}=\frac{61}{25}\)

*************

\(\frac{21}{14}-3,51=\)

\(\frac{3}{2}-\frac{351}{100}=\)

\(\frac{150}{100}-\frac{351}{100}=-\frac{201}{100}\)

إصلاح التمرين رقم 31 صفحة 110

\((\frac{51}{34}+\frac{31}{592})-(\frac{1}{2}+\frac{31}{592})=\)

\((\frac{51}{34})-(\frac{1}{2})=\)

\(\frac{51}{34}-\frac{17}{34}=\frac{34}{34}=1\)

*************

\((\frac{450}{380}-\frac{135}{5972})-(\frac{109}{76}-\frac{135}{5972})=\)

\((\frac{450}{380})-(\frac{109}{76})=\)

\(\frac{450{\color{red}{\div5}}}{380{\color{red}{\div5}}}-\frac{109}{76}=\)

\(\frac{90}{76}-\frac{109}{76}=-\frac{19}{76}\)

إصلاح التمرين رقم 32 صفحة 110

\(\frac{5}{21}\times\frac{14}{15}=\)

\(\frac{5{\color{Red}{\div5}}}{21{\color{blue}{\div7}}}\times\frac{14{\color{blue}{\div7}}}{15{\color{Red}{\div5}}}=\)

\(\frac{1}{3}\times\frac{2}{3}=\frac{2}{9}\)

*************

\(\frac{13}{8}\times\frac{32}{26}=\)

\(\frac{13{\color{Red}{\div13}}}{8{\color{blue}{\div8}}}\times\frac{32{\color{blue}{\div8}}}{26{\color{Red}{\div13}}}=\)

\(\frac{1}{1}\times\frac{4}{2}=\frac{4}{2}=2\)

*************

\(\frac{54}{35}\times\frac{21}{18}=\)

\(\frac{54{\color{Red}{\div18}}}{35{\color{blue}{\div7}}}\times\frac{21{\color{blue}{\div7}}}{18{\color{Red}{\div18}}}=\)

\(\frac{3}{5}\times\frac{3}{1}=\frac{9}{5}\)

*************

\(\frac{5}{13}\times65=\)

\(\frac{5\times(65{\color{Red}{\div13}})}{13{\color{red}{\div13}}}=\)

\(\frac{5\times5}{1}=\frac{25}{1}=25\)

*************

\(\frac{8}{12}\times\frac{5}{17}\times\frac{34}{25}=\)

\(\frac{8{\color{magenta}{\div4}}}{12{\color{magenta}{\div4}}}\times\frac{5{\color{Red}{\div5}}}{17{\color{blue}{\div17}}}\times\frac{34{\color{blue}{\div17}}}{25{\color{Red}{\div5}}}=\)

\(\frac{2}{3}\times\frac{1}{1}\times\frac{2}{5}=\frac{4}{15}\)

*************

\(\frac{15}{8}\times\frac{42}{27}\times\frac{9}{7}=\)

\(\frac{15}{8}\times\frac{42{\color{Red}{\div7}}}{27{\color{blue}{\div9}}}\times\frac{9{\color{blue}{\div9}}}{7{\color{Red}{\div7}}}=\)

\(\frac{15}{8}\times\frac{6}{3}\times\frac{1}{1}=\)

\(\frac{15}{8}\times2=\frac{30}{8}=\frac{15}{4}\)

*************

\(\frac{35000}{2700}\times\frac{18000}{700000}=\)

\(\frac{35000{\color{Red}{\div35000}}}{2700{\color{blue}{\div900}}}\times\frac{18000{\color{blue}{\div900}}}{700000{\color{Red}{\div35000}}}=\)

\(\frac{1}{3}\times\frac{20}{20}=\frac{1}{3}\)

إصلاح التمرين رقم 33 صفحة 110

\(31,5\times\frac{8}{15}=\)

\(\frac{315}{10}\times\frac{8}{15}=\)

\(\frac{315{\color{Red}{\div15}}}{10{\color{blue}{\div2}}}\times\frac{8{\color{blue}{\div2}}}{15{\color{Red}{\div15}}}=\)

\(\frac{21}{5}\times\frac{4}{1}=\frac{84}{5}\)

*************

\(21,4\times\frac{3}{4}=\)

\(\frac{214}{10}\times\frac{3}{4}=\)

\(\frac{214{\color{Red}{\div2}}}{10}\times\frac{3}{4{\color{Red}{\div2}}}=\)

\(\frac{107}{10}\times\frac{3}{2}=\frac{321}{20}\)

*************

\(\frac{8}{3}\times0,93=\)

\(\frac{8}{3}\times\frac{93}{100}=\)

\(\frac{8{\color{Red}{\div4}}}{3{\color{blue}{\div3}}}\times\frac{93{\color{blue}{\div3}}}{100{\color{Red}{\div4}}}=\)

\(\frac{2}{1}\times\frac{31}{25}=\frac{62}{25}\)

*************

\(\frac{75}{24}\times0,66=\)

\(\frac{75}{24}\times\frac{66}{100}=\)

\(\frac{75{\color{Red}{\div25}}}{24{\color{blue}{\div6}}}\times\frac{66{\color{blue}{\div6}}}{100{\color{Red}{\div25}}}=\)

\(\frac{3}{4}\times\frac{11}{4}=\frac{33}{16}\)

*************

\(0\times\frac{35,07}{3}\times\frac{83}{91}=0\)

*************

\(\frac{8}{3}\times\frac{3,5}{10}\times\frac{15}{4}\times\frac{1}{2}=\)

\(\frac{8}{3}\times\frac{35}{100}\times\frac{15}{4}\times\frac{1}{2}=\)

\(\frac{8{\color{Red}{\div4}}}{3}\times\frac{35}{100{\color{blue}{\div5}}}\times\frac{15{\color{blue}{\div5}}}{4{\color{red}{\div4}}}\times\frac{1}{2}=\)

\(\frac{2}{3}\times\frac{35}{20}\times\frac{3}{1}\times\frac{1}{2}=\)

\(\frac{2{\color{Red}{\div2}}}{3{\color{blue}{\div3}}}\times\frac{35}{100}\times\frac{3{\color{blue}{\div3}}}{1}\times\frac{1}{2{\color{Red}{\div2}}}=\)

\(\frac{1}{1}\times\frac{35}{20}\times\frac{1}{1}\times\frac{1}{1}=\frac{35}{20}=\frac{7}{4}\)

إصلاح التمرين رقم 34 صفحة 110

\(20\times\frac{7}{8}=\)

\(20{\color{Red}{\div4}}\times\frac{7}{8{\color{red}{\div4}}}=5\times\frac{7}{2}=\frac{35}{2}\)

*************

\(24\times\frac{7}{8}=\)

\(24{\color{Red}{\div8}}\times\frac{7}{8{\color{red}{\div8}}}=3\times\frac{7}{1}=\frac{21}{1}=21\)

*************

\(4\times\frac{11}{10}=\)

\(4{\color{Red}{\div2}}\times\frac{11}{10{\color{red}{\div2}}}=2\times\frac{11}{5}=\frac{22}{5}\)

*************

\(35\times\frac{13}{35}=\)

\(35{\color{Red}{\div35}}\times\frac{13}{35{\color{red}{\div35}}}=1\times\frac{13}{1}=13\)

عودة إلى صفحة إصلاح كتاب الرياضيات السنة السابعة أساسي